16x^2-44=0

Solution for 16x^2-44=0 equation:

16x^2-44=0

a = 16; b = 0; c = -44;
Δ = b2-4ac
Δ = 02-4·16·(-44)
Δ = 2816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2816}=\sqrt{256*11}=\sqrt{256}*\sqrt{11}=16\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{11}}{2*16}=\frac{0-16\sqrt{11}}{32}
=-\frac{16\sqrt{11}}{32}
=-\frac{\sqrt{11}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{11}}{2*16}=\frac{0+16\sqrt{11}}{32}
=\frac{16\sqrt{11}}{32}
=\frac{\sqrt{11}}{2}
$